OXIDATION-REDUCTION (REDOX) TITRATION

WHAT IS OXIDATION?

During a chemical reaction, loss of electron is non as oxidation
or
During a chemical reaction removal of oxygen and the addition of hydrogen is called oxidation.

WHAT IS REDUCTION?

During a chemical reaction gain of electrons is non as reduction.
or
During a chemical reaction addition of oxygen and removal of hydrogen is called reduction.

Similar to acid-base titration, redox titration is also carried out potentiometrically. In this titration, the electrode is placed in a solution containing both the species’ oxidized and reduced forms, and the electrode, reversible concerning H+ ions, is replaced by inert metal. Here, the electrode act as an oxidation and reduction electrode.
Consider the redox reaction,

\[\displaystyle Fe_{{(aq)}}^{{+2}}+Ce_{{(aq)}}^{{+4}}\rightleftharpoons Fe_{{(aq)}}^{{+3}}+Ce_{{(aq)}}^{{+3}}\]

This reaction involving the oxidation of Fe+2 and ions by Ce+4 ions is transported potentiometrically.

Titration starts with adding Ce+4 ions, in that solution contains only Fe+2 ions, and Fe+2 ions oxidized to Fe+3 ions by adding a small amount of Ce+4 ions in the solution.

 Presence of Fe+2 and Fe+3 ions in the solution, the electrode behaves as an oxidation-reduction electrode in the potential; according to the Nernst equation is,

\[\displaystyle {{E}_{{el}}}=E_{{el}}^{0}+\frac{{RT}}{F}\ln \frac{{\left[ {F{{e}^{{+3}}}} \right]}}{{\left[ {F{{e}^{{+2}}}} \right]}}---(1)\]

At 25˚c

\[\displaystyle =E_{{el}}^{0}+0.0591\log \frac{{\left[ {F{{e}^{{+3}}}} \right]}}{{\left[ {F{{e}^{{+2}}}} \right]}}---(2)\]

Starting an electrode potential is controlled by the ratio of [Fe+3]/[Fe+2]. If the ratio is equal to 0.01, then the electrode potential would be,

\[\displaystyle {{E}_{{el}}}=E_{{el}}^{0}+0.0591\log \left( {0.01} \right)\]
\[\displaystyle ={{E}^{0}}-0.1182\]

With the further addition of Ce+4 ions, the ratio of [Fe+3]/[Fe+2] changes, therefore changing the value of Eel.

For the ten-fold change in the ratio of [Fe+3]/[Fe+2], the electrode’s potential also changes by 0.1182V.

At equivalence point, [Fe+2]= [Ce+4] and [Fe+3]=[Ce+3] that the electrode potential at equivalence point equation Eeq is,

\[\displaystyle {{E}_{{eq}}}=E_{1}^{0}+0.0591\log \frac{{\left[ {F{{e}^{{+3}}}} \right]}}{{\left[ {F{{e}^{{+2}}}} \right]}}=E_{2}^{0}+0.0591\log \frac{{\left[ {C{{e}^{{+4}}}} \right]}}{{\left[ {C{{e}^{{+3}}}} \right]}}---(3)\]

The above equation (3) is also written as,

\[\displaystyle {{E}_{{eq}}}=E_{1}^{0}+0.0591\log \frac{{\left[ {F{{e}^{{+3}}}} \right]}}{{\left[ {F{{e}^{{+2}}}} \right]}}----(4)\]

And,

\[\displaystyle {{E}_{{eq}}}=E_{2}^{0}+0.0591\log \frac{{\left[ {C{{e}^{{+4}}}} \right]}}{{\left[ {C{{e}^{{+3}}}} \right]}}---(5)\]

Adding and simplifying the equivalent point,

\[\displaystyle \left[ {F{{e}^{{+2}}}} \right]=\left[ {C{{e}^{{+4}}}} \right]\]
\[\displaystyle \left[ {F{{e}^{{+3}}}} \right]=\left[ {C{{e}^{{+3}}}} \right]\]

The equation we get,

\[\displaystyle {{E}_{{eq}}}=\frac{{\left( {E_{1}^{0}+E_{2}^{0}} \right)}}{2}---(6)\]

The value of reduction potential of Fe+3 and Ce+4  is 0.77v and 1.61v, respectively.

\[\displaystyle Fe_{{(aq)}}^{{+3}}+{{e}^{-}}\rightleftharpoons Fe_{{(aq)}}^{{+2}};E_{1}^{0}=0.77v\]
\[\displaystyle Ce_{{(aq)}}^{{+4}}+{{e}^{-}}\rightleftharpoons Ce_{{(aq)}}^{{+3}};E_{2}^{0}=1.61v\]

Above the equivalence point [Fe+3] ≈ 0 as s result, the electrode potential is controlled only by the ratio of [Ce+4]/[Ce+3]

For potentiometric measurement, oxidation-reduction electrode (Pt electrode) is combined with a reference electrode, e.g. calomel electrode to form galvanic cell is denoted as,

\[\displaystyle Hg,H{{g}_{2}}C{{l}_{{{{2}_{{(s)}}}}}},KC{{l}_{{\left( {sat.solution} \right)}}}//F{{e}^{{+2}}},F{{e}^{{+3}}};Pt\]

Before the equivalent point, the Emf of the cell is given by,

\[\displaystyle E={{E}_{R}}-{{E}_{L}}\]
\[\displaystyle E_{{el}}^{0}=0.0591\log \left\{ {\frac{{\left[ {F{{e}^{{+3}}}} \right]}}{{\left[ {F{{e}^{{+2}}}} \right]}}} \right\}-{{E}_{{calomel}}}---(7)\]
\[\displaystyle =0.77+0.0591\log \left\{ {\frac{{\left[ {F{{e}^{{+3}}}} \right]}}{{\left[ {F{{e}^{{+2}}}} \right]}}} \right\}-0.24----(8)\]

After the equivalence point, the Emf of a cell is given by,

\[\displaystyle E=1.61+0.0591\log \left\{ {\frac{{\left[ {C{{e}^{{+3}}}} \right]}}{{\left[ {C{{e}^{{+2}}}} \right]}}} \right\}-0.29---(9)\]

At the equivalence point, Emf of a cell is,

\[\displaystyle E=\frac{{0.77+1.61}}{2}-0.24----(10)\]

Emf data obtained are processed for the equivalence point, and Emf of the cell is measured at each stage of titration potentiometrically. Redox titration curve same as Acid-Base titration curve shown Acid-Base Titration Figure (a) and (b).

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About the author

Bhoomika Sheladiya

BSc. (CHEMISTRY) 2014- Gujarat University
MSc. (PHYSICAL CHEMISTRY) 2016 - School of Science, Gujarat University

Junior Research Fellow (JRF)- 2019
AD_HOC Assistant Professor-(July 2016 to November 2021)

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