BENZENE – APPLICATION OF HMO

The secular equation is,

\[\displaystyle \left| \begin{array}{l}x\text{ }1\text{ }0\text{ }0\text{ 0 1}\\1\text{ }x\text{ }1\text{ }0\text{ }0\text{ 0}\\0\text{ 1 }x\text{ 1 0 0}\\\text{0 0 1 }x\text{ 1 0}\\\text{0 0 0 1 }x\text{ 1}\\\text{1 0 0 0 1 }x\end{array} \right|=0----(1)\]

Here,

\[\displaystyle x=\frac{{\left( {\alpha -E} \right)}}{\beta }---(2)\]
Benzene Molecule

Figure1 Benzene Molecule

Which on gives the Polynomial equation,

\[\displaystyle {{x}^{6}}-6{{x}^{4}}+9{{x}^{2}}-4=0---(3)\]

Which roots x=-2; -1 (twice) ; +1 (twice) ; 2

(the inspection of the Polynomial can find these roots)

The energy level is,

\[\displaystyle x=-2:{{E}_{1}}=\alpha +2\beta (BMO)---(4)\]
\[\displaystyle x=-1:{{E}_{2}}={{E}_{3}}=\alpha +\beta \text{(degenerate pair, BMO)}--(5)\]
\[\displaystyle x=+1:{{E}_{4}}={{E}_{5}}=\alpha -\beta \text{(degenerate pair ABMO)}---(6)\]
\[\displaystyle x=+2:{{E}_{6}}=\alpha -2\beta (\text{ABMO)}-----(7)\]
HMO Diagram For Benzene

Figure 2. HMO Diagram For Benzene

Molecular diagram of benzene we can see in figure (2) the occupancy of six  electrons in the three BMOs.

\[\displaystyle {{E}_{\pi }}=2(\alpha +2\beta )+4\left( {\alpha +\beta } \right)\]
\[\displaystyle =6\alpha +8\beta ----(8)\]
\[\displaystyle DE=6\alpha +8\beta -6\left( {\alpha +\beta } \right)\]
\[\displaystyle =-2\beta ----(9)\]

The six normalized HMOs obtained to be,

\[\displaystyle {{\psi }_{1}}=\frac{1}{{\sqrt{6}}}\left( {{{\theta }_{1}}+{{\theta }_{2}}+{{\theta }_{3}}+{{\theta }_{4}}+{{\theta }_{5}}+{{\theta }_{6}}} \right)---(10)\]
\[\displaystyle {{\psi }_{2}}=\frac{1}{2}\left( {{{\theta }_{1}}+{{\theta }_{2}}-{{\theta }_{4}}-{{\theta }_{5}}} \right)-----(11)\]
\[\displaystyle {{\psi }_{3}}=\frac{1}{{\sqrt{{12}}}}\left( {{{\theta }_{1}}-{{\theta }_{2}}-2{{\theta }_{3}}-{{\theta }_{4}}+{{\theta }_{5}}+2{{\theta }_{6}}} \right)---(12)\]
\[\displaystyle {{\psi }_{4}}=\frac{1}{2}\left( {{{\theta }_{1}}-{{\theta }_{2}}+{{\theta }_{4}}-{{\theta }_{5}}} \right)----(13)\]
\[\displaystyle {{\psi }_{5}}=\frac{1}{{\sqrt{{12}}}}\left( {{{\theta }_{1}}+{{\theta }_{2}}-2{{\theta }_{3}}+{{\theta }_{4}}+{{\theta }_{5}}-2{{\theta }_{6}}} \right)---(14)\]
\[\displaystyle {{\psi }_{6}}=\frac{1}{{\sqrt{6}}}\left( {{{\theta }_{1}}-{{\theta }_{2}}+{{\theta }_{3}}-{{\theta }_{4}}+{{\theta }_{5}}-{{\theta }_{6}}} \right)----(15)\]

Benzene is a classic example of delocalization conferring extra stability.

This molecule represents both VBT and MOT, and VBT is used to explain σ framework means each carbon atom sp2 hybridization, while MOT is used to describe π electrons.

Here, resonance integral β ≈ 75 kjmol-1 and DE for benzene ≈ -2β ≈ -150kjmol-1

Two contributions of benzene first are the regular shape of the hexagon is ideal for forming a solid and relaxed σ bond framework. Second, the three HMOs that accommodate the six electrons are all BMOs.

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About the author

Bhoomika Sheladiya

BSc. (CHEMISTRY) 2014- Gujarat University
MSc. (PHYSICAL CHEMISTRY) 2016 - School of Science, Gujarat University

Junior Research Fellow (JRF)- 2019
AD_HOC Assistant Professor-(July 2016 to November 2021)

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